๋ณธ๋ฌธ ๋ฐ”๋กœ๊ฐ€๊ธฐ
โญ Problem_Solving/ํ”„๋กœ๊ทธ๋ž˜๋จธ์Šค

[ํ”„๋กœ๊ทธ๋ž˜๋จธ์Šค] ์กฐ๊ฑด์— ๋งž๋Š” ์‚ฌ์šฉ์ž์™€ ์ด ๊ฑฐ๋ž˜๊ธˆ์•ก ์กฐํšŒํ•˜๊ธฐ(SQL)

by ํฌ์ŠคํŠธ์‰์ดํฌ 2023. 4. 7.

<๋ฌธ์ œ ๋งํฌ>

https://school.programmers.co.kr/learn/courses/30/lessons/164668

 

ํ”„๋กœ๊ทธ๋ž˜๋จธ์Šค

์ฝ”๋“œ ์ค‘์‹ฌ์˜ ๊ฐœ๋ฐœ์ž ์ฑ„์šฉ. ์Šคํƒ ๊ธฐ๋ฐ˜์˜ ํฌ์ง€์…˜ ๋งค์นญ. ํ”„๋กœ๊ทธ๋ž˜๋จธ์Šค์˜ ๊ฐœ๋ฐœ์ž ๋งž์ถคํ˜• ํ”„๋กœํ•„์„ ๋“ฑ๋กํ•˜๊ณ , ๋‚˜์™€ ๊ธฐ์ˆ  ๊ถํ•ฉ์ด ์ž˜ ๋งž๋Š” ๊ธฐ์—…๋“ค์„ ๋งค์นญ ๋ฐ›์œผ์„ธ์š”.

programmers.co.kr

 

<ํ’€์ด ์ „๋žต>

1. where ์ ˆ๊ณผ having ์ ˆ์„ ๋‘˜ ๋‹ค ์ด์šฉํ•ด์•ผ ํ•˜๊ธฐ ๋•Œ๋ฌธ์— sql์—์„œ ์ฟผ๋ฆฌ๋ฌธ์˜ ์‹คํ–‰ ์ˆœ์„œ๋ฅผ ์ž˜ ์•„๋Š” ๊ฒŒ ์ค‘์š”ํ•ฉ๋‹ˆ๋‹ค.

2. ์ถ”๊ฐ€์ ์œผ๋กœ ์‹คํ–‰์ˆœ์„œ์™€ ๊ด€๋ จํ•ด์„œ, ์›๋ž˜ having์€ select ์ด์ „์— ์‹คํ–‰๋˜๊ธฐ ๋•Œ๋ฌธ์— select์—์„œ ์„ค์ •ํ•œ ๋ณ„์นญ์„ ๋ชป ์“ฐ์ง€๋งŒ mysql์—์„œ๋Š” ์˜ˆ์™ธ์ ์œผ๋กœ ํ—ˆ์šฉ์ด ๋ฉ๋‹ˆ๋‹ค.

 

<์ •๋‹ต ์ฝ”๋“œ>

SELECT 
    A.WRITER_ID, 
    B.NICKNAME, 
    SUM(A.PRICE) AS TOTAL_SALES
FROM USED_GOODS_BOARD AS A
JOIN USED_GOODS_USER AS B
ON A.WRITER_ID = B.USER_ID
WHERE STATUS = 'DONE'
GROUP BY A.WRITER_ID
HAVING TOTAL_SALES >= 700000
ORDER BY TOTAL_SALES;

 

๋Œ“๊ธ€